If `A\ a n d\ B` are two independent events such that `P(AnnB)=1/6` a n d\`P(A^'nnB^')=1/3` , then write the values of `P(A)a n d\ P(B)`

Explanation

given,

`P(AnnB)=1/6`

`P(A^'nnB^')=1/3`

So,`1-P(A uu B)=1/3`

`=>P(AuuB)=2/3`

Again,

`P(AuuB)=P(A)+P(B)-P(AnnB)`

`=>2/3=P(A)+P(B)-1/6`

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