Two dice are thrown together. The probability that a lest one will show its digit greater than 3 is
a. 1/4 
   b. 3/4  
 c. 1/2   
  d. 1/8

Explanation

When two dice are thrown, there are `(6×6)=36 ` outcomes

Let E be the event of getting at least one digit greater than `3`


`: .n(E)=27`


Hence, required probability = `(27)/(36)=3/4`