Two dice are thrown simultaneously. the probability of obtaining total score of seven is a. 5/36            b. 6/36            c. 7/36          d. 8/36

Explanation

When two dices are thrown, there are (6×6)=36 outcomes
Let E be the event of getting a total score of `7`


Then `E = {(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)}`


`therefore n(E) = 6`


Hence, required probability = `n(E)n(S)`
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