Two dice are thrown together. The probability that neither they show equal digits nor the sum of their digits is 9 will be a. 13/1            b. 13/18            c. 1/9          d. 8/9

Explanation

To solve the problem, we need to calculate the probability that neither the two dice show equal digits nor the sum of their digits is 9.

### Step-by-Step Solution:

1. **Total Outcomes**:
When two dice are thrown, the total number of possible outcomes is \(6 \times 6 = 36\).

2. **Event E1 (Equal Digits)**:
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