The probabilities of happening of two events A and B are 0.25 and 0.50 respectively. If the probability of happening of A and B together is 0.14, then probability that neither A nor B happen is a. 0.39            b. 0.2            c. 0.11          d. none of these

Explanation

Given that,` P(A) = 0.25, P(B) = 0.50, P(A ∩B) = 0.14.`


The probability that neither `A` nor `B` occurs `= P(A’ ∩B’) = 1-P(AUB)`


Hence, the required probability `= 1- [P(A) + P(B) – P(A ∩B)]`


`= 1- [(0.25)+(0.50) -(0.14)]`


...