The probabilities of three mutually exclusive events A, B and C are given by 2/3,1/4 and 1/6 respectively. The statement. a. is true                              b. is false            c. nothing can be said          d. could be either

Explanation

Given that the probabilities of `3` mutually exclusive events are` 2/3`, `1/4
,` and `1/6`


Let us assume that `A`, `B` and `C` are the three events.


Then, `P(A+B+C) = P(A) + P(B) + P(C)`


`= (2/4)+(1/4)+(1/6)`
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