If three dice are throw simultaneously, then the probability of getting a score of 5 is a. 5/216            b. 1/6            c. 1/36          d. none of these

Explanation

By using binomial distribution,


`p=1/6, q= 5/6, n= 3`


The probability of getting 5 on at least one of the dice is,


`= 3_(C_1)(1/6)(5/6)2 + 3_(C_2)(1/6)2(5/6) + 3_(C_3)(1/6)3(5/6)`


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