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A and B are two events such that P(A)=0....

A and B are two events such that `P(A)=0. 25\ a n d\ P(B)=0. 50.` The probability of both happening together is 0.14. The probability of both A and B not happening is a. 0.39 b. 0.25 c. 0.11 d. none of these

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Given that, `P(A)` `= 0.25, P(B) = 0.50, P(A ∩B)` `= 0.14.`
The probability that neither` A `nor `B` occurs `= P(A’ ∩B’) = 1-P(AUB)`
Hence, the required
probability `= 1- [P(A) + P(B) – P(A ∩B)]`
...
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