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If the probability of A to fall in an examination is `1/5` and that of B is `3/(10)dot` then, the probability that either A or B fails is a. 1/2 b. 11/2 c. 19/50 d. none of these

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Given,
`P(A)=1/5`
`thereforeP(A′)=1−1/5=4/5`
`P(B)=3/(10)`
...
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