Two dice are thrown simultaneously. the probability of getting a pair of aces is a. 1/36            b. 1/3            c. 1/6          d. none of these

Explanation

When two dice are thrown simultaneously, the sample space associated with the random experiment is given by :


`S={(1,1),(1,2),(1,3),.....(6,4),(6,5),(6,6)}`

Clearly, total number of elementary events = 36

Let `A` be the event of getting a pair of aces.

Then `A = {(1, 1)}`

`therefore n(A) = 1`

Hence, required probability = `(n(A))/(n(S))`

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