A box contains 6 nails and 10 nuts. Hal of the nails and half of the nuts are rusted. If one item is chosen at random, the probability that it is rusted or is a nail. a. 3/16            b. 5/16            c. 11/16          d. 14/16

Explanation

Let A be the event that the item chosen is rusted and B be the event that the them chosen is a nail.

`∴P(A)=8/(16)`

`P(B)=6/(16)`

and `P(A∩B)=3/(16)​`

Required
probability=`P(A∪B)=P(A)+P(B)−P(A∩B)`

`=8/(16)​+3/(16)​−6/(16)`

`​=(11)/(16)`