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Without repetition of the numbers, four digit numbers are formed with the numbers `0, 2, 3, 5`. The probability of such a number divisible by 5 is

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The number can't be formed starting zero
So,the total numbers formed start with `2⇒(3!)=6`
the total numbers formed start with `3⇒ (3!)=6`
the total numbers formed start with `5⇒ (3!)=6 `
Then, total no, from `⇒ 18` ways
Now, the no should be divisible with `5` that means now to end with `0` and `5 `
⇒ Such No ⇒ `4+4+2=10`
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