The abscissae and ordinates of the points A and B are the roots of the equations `x^2 + 2ax + b = 0 and x^2 + 2cx + d = 0` respectively, then the equation of circle with AB as diameter is

If the abscissa and ordinates of two points P and Q are the roots of the equations x^2+2a x-b^2=0 and x^2+2p x-q^2=0 , respectively, then find the equation of the circle with P Q as diameter.

If the abscissa and ordinates of two points P and Q are the roots of the equations x^(2)+2ax-b^(2)=0 and x^(2)+2px-q^(2)=0 respectively,then find the equation of the circle with PQ as diameter.

If the abscissa and ordinates of two points Pa n dQ are the roots of the equations x^2+2a x-b^2=0 and x^2+2p x-q^2=0 , respectively, then find the equation of the circle with P Q as diameter.

If the abscissa and ordinates of two points Pa n dQ are the roots of the equations x^2+2a x-b^2=0 and x^2+2p x-q^2=0 , respectively, then find the equation of the circle with P Q as diameter.

If the abscissa and ordinates of two points Pa n dQ are the roots of the equations x^2+2a x-b^2=0 and x^2+2p x-q^2=0 , respectively, then find the equation of the circle with P Q as diameter.

If the abscissa and ordinates of two points Pa n dQ are the roots of the equations x^2+2a x-b^2=0 and x^2+2p x-q^2=0 , respectively, then find the equation of the circle with P Q as diameter.

Abscissas and ordinates of points A and B are roots of equation x^(2) + 2ax - b^(2) = 0 " and " y^(2) + 2py - q^(2) = 0 respectively. Equation of circle with AB as a diameter is

The roots of the equation x^2+ax+b=0 are

If the abscissae and the ordinates of two points A and B be the roots of ax^2+ bx +c=0 and a'y^2+b'y+c'=0 respectively, show that the equation of the circle described on AB as diameter is : aa'(x^2+y^2)+a' bx+ab'y+(ca’ +c'a)=0 .