The theoretically computed equilibrium constant for the polymerisation of formaldehyde to glucose in aqueous solution :
`6HCHO hArr C_6H_12O_6` is `1.0xx10^24` If 1 M-solution of glucose was taken, what should be the equilibrium concentration of formaldehyde ?

The equilibrium constant for the polymerisation of formaldehyde to glucose is aqueous solution is 6 times 10^22. IF 1M glucose is at equilibrium 6HCHO leftrightarrow C_6H_12O_6 what is the concentration of formaldehyde at equilibrium?

Formaldehyde polymerizes to form glucose according to the reaction, 6HCHO rarr C_(6)H_(12)O_(6) The theoretically computed equilibrium constant for this reaction is found to be 6 xx 10^(22) If 1M solution of glucose dissociates according to the above equilibrium, the concentration of formaldehyde in the solution will be :

Formaldehyde polymerizes to form glucose according to the reaction, 6HCHO rarr C_(6)H_(12)O_(6) The theoretically computed equilibrium constant for this reaction is found to be 6 xx 10^(22) If 1M solution of glucose dissociates according to the above equilibrium, the concentration of formaldehyde in the solution will be :

Determine the degree of association (polymerisation) for the reaction in aqueous solution . 6 HCHO hArr C_(6) H_(12) O_(6) . If observed molar mass of HCHO and C_(6) H_(12) O_(6) is 150 :

If 18 gram of glucose (C_6H_(12)O_6) is present in 1000 gram of an aqueous solution of glucose it is said to be-