In an electron gun, the electrons are accelerated by the potential `V`. If the `e` is the charge and `m` is the mass of the electron, then the maximum velocity of these electrons will be

In an electron gun, electron are accelerated through a potential difference of V volt. Taking electronic charge and mass to be respectively 'e' and 'm', the maximum velocity attained by them is

If the electrons are accelerated by a potential of 50V, calculate the de-Broglie wavelength of electrons.

An electron is accelerated from rest to potential V. the final velocity of electron is

An electron of charge e and mass m is acceleration from rest with a potential V. What is the de Broglie wavelength of the electron?

The electrons are accelerated through a pontential difference V by an electron gun. The electron charge and mass are e and m respectively. The maximum velocity attained by them is

An electron is accelerated through a potential difference of 200 volts. If e//m for the electron be 1.6 xx 10^(11) coulomb/kg, the velocity acquired by the electron will be

An electron is accelerated through a potential difference of 200 volts. If e//m for the electron be 1.6 xx 10^(11) coulomb/kg, the velocity acquired by the electron will be

Mention the charge, mass and e/m ratio for an electron.

An electron is accelerated through a potential difference of 1000 volt. The velocity acquired by the electron is