A watt is

A

`kg m//s^(2)`

B

`kg m^(2)//s^(3)`

C

`kg m//s`

D

`kg m^(2)//s^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
Watt `= (J)/(sec)= (N-m)/("sec")=kg.(m^(2))/(sec^(3))`
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