If we use permitivity `epsilon`, resistance `R`, gravitational constant `G` and voltage `V` as fundamental physical quantities, then:

Options

A. [angular displacement]=`epsilon^(1)R^(0)G^(0)V^(0)`
B. [velocity]`=epsilon^(-1)R^(-1)G^(0)V^(0)`
C. [dipole moment] =`epsilon^(1)R^(0)G^(0)V^(1)`
D. [force]=`epsilon^(2)F^(0)G^(0)V^(2)`

Answer

B

Explanation

`epsilon=(I^(2)T^(4))/(ML^(3)),R=(ML^(2))/(I^(2)T^(3)), G=(L^(3))/(MT^(2)),V=(ML^(2))/(IT^(3))`
`theta=M^(0)L^(0)T^(0)`, velocity `(L)/(T)`, force `(ML)/(T^(2))`, dipole moment =LIT