In the figure given below, the position time graph of a particle of mass 0.1kg is shown. The impulse at t=2 sec is

Options

A. `0.2 gk m//sec`
B. `-0.2 kg m sec^(-1)`
C. `0.1 kg m sec^(-1)`
D. `-0.1 kg m//sec`

Answer

B

Explanation

Corresponding velocity -time graph is

Accordingly, change in momentum at t=2 sec is
`Deltap=p_(f)-p_(i) =0.1xx0-0.1xx2=0.2`
or impulse =-0.2 kg m/s