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In the figure given below, the position ...

In the figure given below, the position time graph of a particle of mass 0.1kg is shown. The impulse at t=2 sec is

A

`0.2 gk m//sec`

B

`-0.2 kg m sec^(-1)`

C

`0.1 kg m sec^(-1)`

D

`-0.1 kg m//sec`

Text Solution

Verified by Experts

The correct Answer is:
B
Corresponding velocity -time graph is

Accordingly, change in momentum at t=2 sec is
`Deltap=p_(f)-p_(i) =0.1xx0-0.1xx2=0.2`
or impulse =-0.2 kg m/s
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Knowledge Check

  • In the figure given below, the position-time graph of a particle of mass 0.1kg is shown. The impuslse at t=2 sec is

    A
    `0.2kgm//sec`
    B
    `-0.2kgm//sec`
    C
    `-0.1kgm//sec`
    D
    `-0.4kgm//sec`

  • In the figure given below, the position–time graph of a particle of mass 0·1 kg is shown. The impulse at t=2 sec is

    A
    `0*2" kgmsec "^(-1)`
    B
    `-0*2" kgmsec "^(-1)`
    C
    `0*1" kgmsec "^(-1)`
    D
    `-0*4" kgmsec "^(-1)`

  • In the figure given, the position-time graph of a particle of mass 0.1 kg is shown the impulse at t = 2s is

    A
    0.2 kg m/s
    B
    `-0.2` kg m/s
    C
    0.1 kg m/s
    D
    `-0.4` kg m/s

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