A weight w is to be moved from the bottom to the top of an inclined plane of inclination `theta` to the horizontal. If a smaller force is to be applied to drag it along the plane in comparison to lift it vertically up, the coefficient of friction should be such that.

Options

A. `mugt tan((pi)/2-(theta)/2)`
B. `mult tan((pi)/2-(theta)/2)`
C. `mu lt tan theta`
D. `mugt tan. (pi)/(4)`

Answer

B

Explanation

`F_(1)=w sin theta+mu w cos theta`
`F_(2)=w`
As, `F_(1) lt F_(2)`
`:. mu lt tan((pi)/4-(theta)/2)`