A block of mass `15 kg` is resting on a rough inclined plane as shown in figure ,The block is tied by a horizontal string which has a tension `50 N` The coefficient of friction of contact is

Options

A. `1//2`
B. `2//3`
C. `3//4`
D. `1//4`

Answer

A

Explanation

The free body diagram of the block is N is the normal reaction exerted by inclined plane on the block. Applying Newton's second law to the block along and normal to the incline. `mg sin 45^(@)=T cos 45^(@) +muN....(1)`
`N=mg cos 45^(@)+T sin 45^(@)......(2)`
Solving we get
`mu=1//2`