A block is given velocity 10 m/s along the fixed inclined as shown in figure from the bottom of the inclined plane. Find the total distance travelled along the inclined plane. If the coefficient of friction is equal to 0.5

Options

A. `5m`
B. `10m`
C. `(25)/(3) m`
D. `(50)/(3) m`

Answer

B

Explanation

Distance travelled along plane till it stops
`s=((10)^(2))/(2(g sin 37^(@)+mu cos 37^(@)))=5m`
But friction force is not sufficient to stope there, so it will come back to the bottom of the inclined plane.
Total distance travelled =5+5=10 m