Car is accelerating with acceleration `=20 m//s^(2)`. A box of mass m=10 kg that is placed inside the car, it is put in contact with the vertical wall of car as shown. The friction coefficient between the box and the wall `mu=0.6`

Options

A. The acceleration of the box will be `10 m//s^(2)`
B. The friction force acting on box will be 100 N
C. The contact force between the vertical wall and the box will be 100N
D. None of these

Answer

B

Explanation

The breaking force is insufficient, so the block will not slide

So friction force =100 N
and acceleration will be `20 m//sec^(2)` only
`20 m//sec^(2)`
Net contact force on the block =`sqrt((200)^(2)+(100)^(2))=100sqrt(5) N`