An elevatore weighinig 500kg is to be li...

An elevatore weighinig 500kg is to be lifted up at a constant velocity of `0*4m//s`. What should be the minimum horse power of the motor to be used ?

1000 W

5000 W

3000 W

2000 W

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The correct Answer is:

`P=F.v.mgv=500xx10xx0.4 W`
=2000W

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