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For a body in circular motion with a con...

For a body in circular motion with a constant angular velocity, the magnitude of the average acceleration over a period of half a revolution is how many times the magnitude of its instantaneous acceleration?

A

`1/pi`

B

`2/pi`

C

`5/pi`

D

`3/pi`

Text Solution

Verified by Experts

The correct Answer is:
B
ltagt =average acceleration
`=(Deltav)/(Deltat)=(2 omegaR)/(piR//omegaR)`
`=(2R omega^(2))/(pi)`
Instantaneous acceleration =`omega^(2)R`
`( lt a gt)/a=2/(pi)`
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Knowledge Check

  • For a body in circular motion with a constant angular velocity, the magnitude of the average acceleration over a period of half a revolution is … times the magnitude of its instantaneous acceleration.

    A
    `2/pi`
    B
    `pi/2`
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  • A body moves with constant angular velocity on a circle. Magnitude of angular acceleration

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    C
    Zero
    D
    None of the above

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    A
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    B
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    C
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    D
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