A ball of mass m strikes the fixed inclined plane after falling through a height h. if it rebounds elastically. The impulse on the ball is :

Options

A. `2 m cos thetasqrt(2gh)`
B. `2 m cos thetasqrt(gh)`
C. `(2msqrt(2gh))/(cos theta)`
D. `2msqrt(2gh)`

Answer

A

Explanation

Here e=1
If ball rebound elastically
`V_(Lol)=u_(Lol)`
`:. ` Along line of impact momentum conservation
`intNdt=mv-(-m u) =mv+m u=2 m u`
Along Lol =`u_(LOL)=u cos theta `
`=sqrt(2gh) cos theta`
`J=2m cos theta .sqrt(2gh)`