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Two points of a rod move with velocity 3...

Two points of a rod move with velocity `3 v` and `v` perpendicular to the rod and in the same direction. Separated by a distance `r`. Then the angular velocity of the rod is :

A

`(3v)/r`

B

`(4v)/r`

C

`(5v)/r`

D

`(2v)/r`

Text Solution

Verified by Experts

The correct Answer is:
D
`omega_(rod)=omega_("Point")=((v_(rel))/r)` , `v_(rel)` being the velocity of one point w.r.t other.
`=(3v-v)/r` and r' being the distance between them
`=(2v)/r`
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