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If vec(tau)xxvec(L)=0 for a rigid body, ...

If `vec(tau)xxvec(L)=0` for a rigid body, where `vec(tau)=` resultant torque & `vec(L)` =angular momentum about a point and both are non-zero. Then

A

`vec(L)=`constant

B

`|vec(L)|`=constant

C

`|vec(L)|` will increases

D

`|vec(L)|` may increase

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Verified by Experts

The correct Answer is:
D

`sin theta=0` so `theta=0, pi`
In case of `theta=0, vec(L)` will increases
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