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A particle falls freely near the surface...

A particle falls freely near the surface of the earth. Consider a fixed point `O` (not vertically below the particle) on the ground.

A

Angular momentum of the particle about O is increasing

B

Torque of the gravitational force on the particle about O is decreasing

C

The moment of inertia of the particle about O is decreasing

D

The angular velocity of the particle about O is increasing.

Text Solution

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The correct Answer is:
B
The magnitude of angular momentum of particle about O=mvd
Since speed v of particle increases, its angular momentum about O increases.
Magnitude of torque of gravitational force about O=mgd `rArr` constant.
Hence MI of particle about O decreases.

angular velocity of particle about `O=(v sin theta)/r`
`:'` v and `sin theta` increases and r decreases
`:.` angular velocity of particle about O increases.
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