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A particle performing uniform circular motion gas angular momentum `L`. If its angular frequency is double and its kinetic energy halved, then the new angular momentum is :

A

2L

B

4L

C

L/2

D

L/4

Text Solution

Verified by Experts

The correct Answer is:
D

Kinetic energy =`1/2 L omega`
`(K_(1))/(K_(2))=(L_(1)omega_(1))/(L_(2)omega_(2))`
`L_(2)=L//4`
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