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Equation of two S.H.M. x(1)=5 sin (2pi t...

Equation of two S.H.M. `x_(1)=5 sin (2pi t+pi//4),x_(2)=5sqrt(2)(sin 2pit+cos 2pit)` ratio of amplitude & phase difference will be

A

`2:1,0`

B

`1:2,0`

C

`1:2,pi//2`

D

`2:1,pi//2`

Text Solution

Verified by Experts

The correct Answer is:
B
`x_(1)=5 sin (2pit+pi//4)`
`x_(2)=5.sqrt(2)(sin 2pi t+cos 2pi t)`
`x_(2)=10 sin (2pit+pi//4)`
So, ratio amplitude 1:2 and phase difference is zero
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Knowledge Check

  • Two S.H.M. s are represented by the equation x_(1)=3"sin" (2pi t+(pi)/(4)) " and " x_(2)=3sqrt(2)["sin" (2pi t)+"cos"(2pi t)] What is the ratio of the amplitudes of x_(1) " and " x_(2) ?

    A
    `2 :1`
    B
    `1 : 2`
    C
    `1 : 3`
    D
    `sqrt(3) : 1`
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