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The amplitude of a particle performing S...

The amplitude of a particle performing `SHM` is 'a'. The displacement at which its velocity will be half the maximum velocity is

A

`(sqrt(3))/2 a`

B

`3/(sqrt(2))a`

C

`a//2`

D

a

Text Solution

Verified by Experts

The correct Answer is:
A
`v=omegasqrt(a^(2)-x^(2))`
`(aomega)/2=omegasqrt(a^(2)-x^(2))`
`x=(sqrt(3))/(2)a`
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RESONANCE-SIMPLE HARMONIC MOTION-Exercise
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  2. A particle is executing a simple harmonic motion its maximum accelerat...

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  7. The graph in the figure shows how the displacement of a particle descr...

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  9. A particle is executing SHM with an amplitude 4 cm. the displacment at...

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  10. For a particle executing S.H.M. which of the following statements hold...

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  11. The equation of SHM of a particle is (d^2y)/(dt^2)+ky=0, where k is a ...

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  12. The total energy of the body excuting S.H.M. is E . Then the kinetic e...

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  13. A linear harmonic oscillator of force constant 2 xx 10^6 N//m and ampl...

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  14. A particle excuting S.H.M. of amplitude 4 cm and T = 4 sec .The time t...

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  15. The potential energy of a particle execuring S.H.M. is 2.5 J, when its...

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  16. A body of mass m is suspended from three springs as shown in figure. I...

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  17. One mass m is suspended from a spring. Time period of oscilation is T....

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  18. A spring has a certain mass suspended from it and its period for verti...

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  19. Two objects A and B of equal mass are suspended from two springs const...

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