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The total energy of the body excuting S....

The total energy of the body excuting `S.H.M.` is `E` . Then the kinetic energy when the displacement is half of the amplitude, is

A

`E/2`

B

`E/4`

C

`(3E)/(4)`

D

`(sqrt(3))/4E`

Text Solution

Verified by Experts

The correct Answer is:
C
Kinetic energy =`1/2momega^(2)(a^(2)-x^(2))`
Kinetic energy=`1/2 (3/4 momega^(2)a^(2))=(3E)/4`
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