One mass m is suspended from a spring. Time period of oscilation is T. now if spring is divided into n pieces & these are joined in parallel order then time period of oscillation if same mass is suspended.

Options

A. `2pisqrt((n^(2)m)/k)`
B. `2pisqrt((n^(2)k)/m)`
C. `2pisqrt(m/(n^(2)k))`
D. `2pisqrt(k/(n^(2)m))`

Answer

C

Explanation

`T=2pisqrt(m/k)`
And spring is devided into n piece and connected in parallel combination then `k_(eq)=n^(2)xxk`
So new time period `=2pisqrt(m/(n^(2)k))`