A spring has a certain mass suspended from it and its period for vertical oscillations is `T_(1)`. The spring is now cut into two equal halves and the same mass is suspended from one of the half. The period of vertical oscillation is now `T_(2)`. The ratio of `T_(2)//T_(1)` is

Options

A. `1//2`
B. `1//sqrt(2)`
C. `sqrt(2)`
D. `2`

Answer

B

Explanation

`T=2pisqrt(m/k)`
When spring is cut in part, then force constant is `k/2`
So, `(T_(2))/(T_(1))=1//sqrt(2)`