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Two objects A and B of equal mass are su...

Two objects A and B of equal mass are suspended from two springs constants `k_(A)` and `k_(B)` if the objects oscillate vertically in such a manner that their maximum kinetic energies are equal, then the ratio of their amplitudes is

A

`(K_(B))/(K_(A))`

B

`sqrt((K_(B))/(K_(A)))`

C

`(K_(A))/(K_(B))`

D

`sqrt((K_(A))/(K_(B)))`

Text Solution

Verified by Experts

The correct Answer is:
B
Kinetic energy of A =Kinetic energy of B
`1/2 K_(A)a^(2)=1/2 K_(B)b^(2)`
So ratio of amplitude `=sqrt((K_(B))/(K_(A)))`
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