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two particle of medium disturbed by the wave propagation are at `x_(1)=0 and x_(2)=1 cm`. The respective displacement (in cm) of the particles can be given by the equation:
`y_(1)=2 sin 3pi t, y_(2) sin (3pi t-pi//8)` the wave velocity is

A

16 cm/sec

B

24 cm/sec

C

12 cm/sec

D

8 cm/sec

Text Solution

Verified by Experts

The correct Answer is:
B
Given `omega=3pi`
`:. f=(omega)/(2pi)=1.5`,
Also `Deltax=1.0 cm`
Given `phi=(2pi)/(lambda) DeltaxrArr (pi)/8=(2pi)/(lambda)xx1`
`rArr lambda=16 cm " " v= f lambda=16xx1.5 =24 cm //sec`
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Knowledge Check

  • y_(t)=2sin3pit y_(2)=2sin(3pit-(pi)/(8)) The wave velocity is

    A
    `16cm//sec`
    B
    `24cm//sec`
    C
    `12cm//sec`
    D
    `8cm//sec`

  • Two particles of a medium disturbed by the wave propagtion are at x_(1)=0 and x_(2)=1 cm The wave is propagating in positive x-direction The displacement of the particles is given by the equation: y_(1)=(2sin3pit) cm and y_(2)=2sin(3pit-pi//8) cm (t is in seconds)

    A
    The frequency of wave is `1.5` Hz
    B
    Wavelength of the wave can be 16 cm
    C
    Velocity of the wave can be 24 cm//s
    D
    Wave equation can be `y=(2)sin[(2pi)/16(24t-x)]` cm.

  • Two particles of of a medium disturbed by the wave propagation are at x_(1) = 0 and x_(2) = 1 cm . The wave is propagating in positive x-direction. The displacement of the particles is given by the equation : y_(1) = (2sin3pit)cm and y_(2) = 2sin(3pit- pi//8)cm (t is in second

    A
    The frequency of wave is `1.5` Hz
    B
    wavelength of the wave can be `16` cm.
    C
    Velocity of the wave can be `24 cm//s`
    D
    Wave equation can by `y = (2) sin [(2pi)/(16)(24t-x)]cm`.
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