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two particle of medium disturbed by the wave propagation are at `x_(1)=0 and x_(2)=1 cm`. The respective displacement (in cm) of the particles can be given by the equation:
`y_(1)=2 sin 3pi t, y_(2) sin (3pi t-pi//8)` the wave velocity is

A

16 cm/sec

B

24 cm/sec

C

12 cm/sec

D

8 cm/sec

Text Solution

Verified by Experts

The correct Answer is:
B
Given `omega=3pi`
`:. f=(omega)/(2pi)=1.5`,
Also `Deltax=1.0 cm`
Given `phi=(2pi)/(lambda) DeltaxrArr (pi)/8=(2pi)/(lambda)xx1`
`rArr lambda=16 cm " " v= f lambda=16xx1.5 =24 cm //sec`
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Knowledge Check

  • y_(t)=2sin3pit y_(2)=2sin(3pit-(pi)/(8)) The wave velocity is

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    B
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  • Two particles of a medium disturbed by the wave propagtion are at x_(1)=0 and x_(2)=1 cm The wave is propagating in positive x-direction The displacement of the particles is given by the equation: y_(1)=(2sin3pit) cm and y_(2)=2sin(3pit-pi//8) cm (t is in seconds)

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  • Two particles of of a medium disturbed by the wave propagation are at x_(1) = 0 and x_(2) = 1 cm . The wave is propagating in positive x-direction. The displacement of the particles is given by the equation : y_(1) = (2sin3pit)cm and y_(2) = 2sin(3pit- pi//8)cm (t is in second

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    wavelength of the wave can be `16` cm.
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