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What is the second lowest frequency for standing waves on a wire that is 10.0 m long has a mass of 100 g and is stretched under a tension of 25 N which is fixed at both ends ?

A

2.5 Hz

B

5.0 Hz

C

7.5 Hz

D

10.0 HZ

Text Solution

Verified by Experts

The correct Answer is:
B

`v=sqrt(T/(mu))=sqrt(25)/((100xx10^(-3))/(10))=50 `
`:. v_(0)=v/(2L)=50/(2xx10)=2.5 Hz`
`:. v_(1)=2v_(0)=5Hz`
`v_(2)=3v_(0)=7.5 Hz`
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