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The density of the material of a wire us...

The density of the material of a wire used in sonometer is `75xx10^(-2) kg //m^(3)`. If the stress on the wire is `3.0xx10^(4) N//m^(2)`, the speed of transverse wave in the wire will be

A

100 m/s

B

200 m/s

C

300 m/s

D

400 m/s

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The correct Answer is:
To find the speed of transverse waves in the wire, we can use the formula derived from Newton's laws: \[ v = \sqrt{\frac{\text{stress}}{\text{density}}} \] ### Step 1: Identify the given values - Density of the material of the wire, \( \rho = 75 \times 10^{-2} \, \text{kg/m}^3 \) - Stress on the wire, \( \sigma = 3.0 \times 10^{4} \, \text{N/m}^2 \) ### Step 2: Substitute the values into the formula Now, we substitute the values of stress and density into the formula: \[ v = \sqrt{\frac{3.0 \times 10^{4}}{75 \times 10^{-2}}} \] ### Step 3: Simplify the expression First, we need to simplify the denominator: \[ 75 \times 10^{-2} = 0.75 \, \text{kg/m}^3 \] Now, substituting this back into the equation: \[ v = \sqrt{\frac{3.0 \times 10^{4}}{0.75}} \] ### Step 4: Calculate the division Calculating the division: \[ \frac{3.0 \times 10^{4}}{0.75} = 4.0 \times 10^{5} \] ### Step 5: Take the square root Now, we take the square root: \[ v = \sqrt{4.0 \times 10^{5}} = 2000 \, \text{m/s} \] ### Final Answer Thus, the speed of the transverse wave in the wire is: \[ v = 2000 \, \text{m/s} \] ---

To find the speed of transverse waves in the wire, we can use the formula derived from Newton's laws: \[ v = \sqrt{\frac{\text{stress}}{\text{density}}} \] ### Step 1: Identify the given values - Density of the material of the wire, \( \rho = 75 \times 10^{-2} \, \text{kg/m}^3 \) ...
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