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A spherical drop of water as 1mm radius....

A spherical drop of water as `1mm` radius. If the surface tension of the the water is `50xx10^-3(N)/(m)`, then the difference of pressure between inside and outside the spherical drop is:

A

`25 N//m^(2)`

B

`10000 N//m^(2)`

C

`100 N//m^(2)`

D

`50 N//m^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`P_("excess")=(2T)/R=(2(50xx10^(-3)))/((10^(-3)))=100 N//m^(2)`
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