A particle of charge `-q` and mass m moves in a circle of radius r around an infinitely long line charge of linear charge density `+lamda`. Then, time period will be
where , `k=1/4piepsilon_0)`

Options

A. `T=2pir sqrt(m/(2k lambdaq))`
B. `T^(2)=(4pi^(2) m)/(2k lambda q)`
C. `T=1/(2pir)sqrt((2klambdaq)/m)`
D. `T=1/(2pir) sqrt(m/(2k lambdaq))`

Answer

A

Explanation

We have centripetal force equation
`q=((2klambda)/r)=(mv^(2))/r`
So, `v=sqrt((2kq lambda)/m)` Now, `T=(2pir)/v=2pirsqrt(m/(2klambdaq))`
where, `k=1/(4piepsilon_(0))`