Home
Class 11
PHYSICS
The magnitude of electric field intensit...

The magnitude of electric field intensity at point `B(2,0,0)` due to dipole of dipole moment, `vec(p)=hat(i)+sqrt(3)hat(j)` kept at origin is (assume that the point `B` is at large distance from the dipole and `k=(1)/(4pi epsilon_(0)))`

A

`(sqrt(13)K)/8`

B

`(sqrt(13) k)/4`

C

`(sqrt(7)k)/8`

D

`(sqrt(7)k)/4`

Text Solution

Verified by Experts

The correct Answer is:
C

The dipole moment makes an angle `60^(@)` with x-axis and lies in x-y plane as shown in figure

The electric field at point A due to dipole's
`E=(kP)/(r^(3)) sqrt(1+3 cos^(2)theta)` where `theta=60^(@)` `:. E=(sqrt(7)K)/8`
Alternate solution
The dipole of moment P can be taken as combination of two dipole moments `vec(P)_(1)=hati` and `vec(P)_(2)=sqrt(3)hatj` as shown in figure

the electric field at point A is
`vec(E)=k(2vec(P)_(1))/(r^(3))-k(vec(P)_(2))/(r^(3))=k[(2hati)/(2^(3))-(sqrt(3)hatj)/(2^(3))]rArr |vec(E)|=(sqrt(7)K)/8`
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC INDUCTION

    RESONANCE|Exercise Exercise|43 Videos
  • FLUID MECHANICS

    RESONANCE|Exercise Advanced Level Problems|8 Videos

Similar Questions

Explore conceptually related problems

The magnitude of electric field intensity at point B(x,0,0) due to a dipole of dipole moment , vec(P) - P_(0) ( hat(i) + sqrt(3)hat(j)) kept at origin is sqrt(n) ((kp_(0))/(r^(3))) , find n (assume that the point is at large distance form the diople , k = (1)/(4 pi in_(0)) .

The magnitude of electric field intensity at point (2,0,0) due to a dipole of dipole moment, vec P=hat i+sqrt(3)hat j kept at origin is where k=1/4 pi varepsilon_(0) is , (sqrt(m)k)/(n) then n-m is-

Find out the magnitude of electric field intensity and electric potential due to a dipole of dipole moment vec(P)=hat(i)+sqrt(3)hat(j) kept at origin at following points. (i) (2, 0, 0) (ii) (-1, sqrt(3), 0)

The electric field intensity vec(E) , , due to an electric dipole of dipole moment vec(p) , at a point on the equatorial line is :

The magnitude of electric field intensity at a point on the axis of short dipole is 30V/m. The distance of the point from the centre of the dipole is 2m. Then potential at that point is

An electric dipole of moment overset( r ) (p) = (hat(i) + 2hat ( j )) xx10^(-28) Cm is at origin. The electric field at point ( 2,4) due to the dipole is parallelto

Electric potential due to a dipole at a position vec r from its centre is: where (K = 1/(4pi epsilon_0)

An electric dipole with dipole moment vec p=(3hati +4hatj) C-m is kept in electric field vec E=0.4hatk N/C .What is the torque acting on it and the potential energy of the dipole?

Two point electric dipoles with dipole moment P_(1) and P_(2) are separated by a distance r with their dipole axes mutually perpendicular as shown. The force of interaction between the dipoles is (where k=(1)/(4piepsilon_(0)) )

RESONANCE-ELECTROSTATICS-Exercise
  1. Total electric force on an electric dipole placed in an electric field...

    Text Solution

    |

  2. Electric potential due to a dipole at a position vec r from its centre...

    Text Solution

    |

  3. The magnitude of electric field intensity at point B(2,0,0) due to dip...

    Text Solution

    |

  4. Consider the four field patterns shown. Assuming there are no charge i...

    Text Solution

    |

  5. If the net electric field flux passing through a closed surface is zer...

    Text Solution

    |

  6. Eight point charges (can be assumed as small spheres uniformly charged...

    Text Solution

    |

  7. Figure above shows a closed Gaussian surface in the space of a cube of...

    Text Solution

    |

  8. Electrical potential V in space as a function of co-ordinates is given...

    Text Solution

    |

  9. S1: In a metallic body total number of electrons is very large in comp...

    Text Solution

    |

  10. S1: When a positively charged particle is released in an electric fiel...

    Text Solution

    |

  11. A point charge q is located at the centre fo a thin ring of radius R ...

    Text Solution

    |

  12. Two small balls having equal positive charge Q (coulumb) on each suspe...

    Text Solution

    |

  13. A point charge q moves from point P to pont S along the path PQRS (fig...

    Text Solution

    |

  14. A large nonconducting sheet M is given a uniform charge density. Two u...

    Text Solution

    |

  15. At a distance of 5 cm and 10 cm outward from the surface of a uniforml...

    Text Solution

    |

  16. An electric dipole is kept in the electric field produced by a point c...

    Text Solution

    |

  17. The electric potential decreases uniformly from 180V to 20V as one mov...

    Text Solution

    |

  18. Two positive point charges each of magnitude 10 C are fixed at positio...

    Text Solution

    |

  19. A square loop of side 'l' having uniform linear charge density 'lambda...

    Text Solution

    |

  20. In the following figure an isolated charged conductor is shown. The co...

    Text Solution

    |