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A parallel plate air capacitor is charge...

A parallel plate air capacitor is charged to a potential difference of `V` volts. After disconnecting the charging battery the distance between the plates of the capacitor is increased using an isulating handle. As a result the potential difference between the plates

A

decreases

B

does not change

C

becomes zero

D

increases

Text Solution

Verified by Experts

The correct Answer is:
D
`C=(epsilonA)/d` if d increases then C decreases
q=CV here q is constant so V increases
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