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A capacitor of 6mu F is charged to such ...

A capacitor of `6mu F` is charged to such an extent that the potential difference between the plates becomes 50V. The work done in this process will be

A

`7.5xx10^(-2)J`

B

`7.5xx10^(-3)J`

C

`3xx10^(-6)J`

D

`3xx10^(-3)J`

Text Solution

Verified by Experts

The correct Answer is:
B
`W=1/2 CV^(2)=1/26xx(50)^(2)xx10^(-6) =7.5xx10^(-3) J`
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