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A capacitor of capacitance 500muF is cha...

A capacitor of capacitance `500muF` is charged at the rate of `100muC//s`. The time in which the potential difference will become 20V, is :

A

100s

B

50 s

C

20 s

D

10 s

Text Solution

Verified by Experts

The correct Answer is:
A
`(dq)/(dt)=C(dv)/(dt)`
`(dV)/(dt)=0.2 V//s`
`V=((dV)/(dt))Deltat`
`Deltat=100s`
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