If the two plates of the charged capacitor are connected by a wire, then

Options

A. potential will becomes infinte
B. charge will becomes infinite
C. capacitor will get discharged
D. charge will becomes double that of earlier one

Explanation

To solve the question regarding what happens when the two plates of a charged capacitor are connected by a wire, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Initial Condition**:
- A capacitor consists of two plates, one positively charged (+Q) and the other negatively charged (-Q). The potential difference (V) between the plates is given by the formula:
\[ V = \frac{Q}{C} \]
where \(Q\) is the charge and \(C\) is the capacitance.

2. **Connecting the Plates with a Wire**:
- When the two plates of the charged capacitor are connected by a wire, they are effectively at the same electrical potential. This means that the potential difference (V) between the two plates becomes zero:
\[ V = 0 \]

3. **Implications of Zero Potential Difference**:
- Since the potential difference is zero, we can use the relationship \(V = \frac{Q}{C}\) to deduce the charge on the plates. If \(V = 0\), then:
\[ Q = 0 \times C = 0 \]
This indicates that the charge on both plates will become zero.

4. **Conclusion**:
- By connecting the plates with a wire, the capacitor will discharge completely, and the charge on both plates will become zero. Therefore, the correct answer is that the capacitor will get discharged.

### Final Answer:
The capacitor will get discharged (Option 3).