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An air capacitor is charged upto a poten...

An air capacitor is charged upto a potential `V_1`. It is connected in parallel to an identical uncharged capacitor filled with a dielectric medium. After redistribution of charge if the potential difference of this combination is V, then the dielectric constant of the substance will be

A

`V^(2)(V_(1)-V)`

B

`V(V_(1)-V)`

C

`V/((V_(1)-V))`

D

`((V_(1)-V))/V`

Text Solution

Verified by Experts

The correct Answer is:
D
`V=(CV_(1))/(C+KC)rArr K=(V_(1)-V)/V`
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