After charging a capacitor the battery is removed. Now by placing a dielectric slab between the plates

Options

A. the potential difference between the plates and the energy stored will decreases but the charge on plates will remains same
B. the charge on the plates will decreases and the potential difference between the plates will increases
C. the potential difference between the plates will increases and energy stored will decreases but the charge on the plates will remains same
D. the potential difference, energy stored and the charge will remain unchanged

Answer

A

Explanation

Battery is removed, charge on plate is constant. By placing a dielectric slab between the plates, capacitances increases so that potential difference between the plates and energy stored will decreases