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Between the plates of a parallel plate c...

Between the plates of a parallel plate condenser, a plate of thickness `t_(1)` and dielectric constant `k_(1)` is placed. In the rest of the space, there is another plate of thickness `t_(2)` and dielectric constant `k_(2)`. The potential difference across the condenser will be

A

`Q/(Aepsilon_(0))((t_(1))/(k_(1))+(t_(2))/(k_(2)))`

B

`(epsilon_(0)Q)/A((t_(1))/(k_(1))+(t_(2))/(k_(2)))`

C

`Q/(Aepsilon_(0))((k_(1))/(t_(1))+(k_(2))/(t_(2)))`

D

`(epsilon_(0)Q)/A(k_(1)t_(1)+k_(2)t_(2))`

Text Solution

Verified by Experts

The correct Answer is:
A

`1/(C_(eq))=(t_(1))/(k_(1)epsilon_(0)A)+(t_(2))/(k_(2)epsilon_(0)A)`
`V=Q/(C_(eq))=Q/(epsilon_(0)A)((t_(1))/(K_(1))+(t_(2))/(K_(2)))`
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