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When the number of turns in a toroidal c...

When the number of turns in a toroidal coil is doubled, then the value of magnetic flux density will becomes-

A

four times

B

eight times

C

half

D

double

Text Solution

Verified by Experts

The correct Answer is:
D
`Bxx2piR=mu_(0) xxN.i`
`B=(mu_(0).i)/(2piR).N`
`B prop N`
So the magnetic field will be double.
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