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A particle of mass `0.6g` and having charge of `25 n_(C)` is moving horizontally with a uniform velocity `1.2xx10^(4)ms^(-1)` in a uniform magnetic field, then the value of the magnetic induction is `(g=10ms^(-2))`

A

zero

B

10 T

C

20 T

D

200 T

Text Solution

Verified by Experts

The correct Answer is:
C
`m=0.6 gm, q=25 nC, v=1.2xx10^(4)ms^(-1)`
`:' mg =B.qv, B=(mg)/(qv)`
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